(3x+3)(3x-3)=9x^2-9

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Solution for (3x+3)(3x-3)=9x^2-9 equation: 


Simplifying
(3x + 3)(3x + -3) = 9x2 + -9

Reorder the terms:
(3 + 3x)(3x + -3) = 9x2 + -9

Reorder the terms:
(3 + 3x)(-3 + 3x) = 9x2 + -9

Multiply (3 + 3x) * (-3 + 3x)
(3(-3 + 3x) + 3x * (-3 + 3x)) = 9x2 + -9
((-3 * 3 + 3x * 3) + 3x * (-3 + 3x)) = 9x2 + -9
((-9 + 9x) + 3x * (-3 + 3x)) = 9x2 + -9
(-9 + 9x + (-3 * 3x + 3x * 3x)) = 9x2 + -9
(-9 + 9x + (-9x + 9x2)) = 9x2 + -9

Combine like terms: 9x + -9x = 0
(-9 + 0 + 9x2) = 9x2 + -9
(-9 + 9x2) = 9x2 + -9

Reorder the terms:
-9 + 9x2 = -9 + 9x2

Add '9' to each side of the equation.
-9 + 9 + 9x2 = -9 + 9 + 9x2

Combine like terms: -9 + 9 = 0
0 + 9x2 = -9 + 9 + 9x2
9x2 = -9 + 9 + 9x2

Combine like terms: -9 + 9 = 0
9x2 = 0 + 9x2
9x2 = 9x2

Add '-9x2' to each side of the equation.
9x2 + -9x2 = 9x2 + -9x2

Combine like terms: 9x2 + -9x2 = 0
0 = 9x2 + -9x2

Combine like terms: 9x2 + -9x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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